Correct Answer - A
Taking `O` as the origin,let the position vectors of `A,B` and `C` be `veca, vecb` and `vecc` respectively. Then, the position vectors of `G_(1),G_(2)` and `G_(3)` are `(vecb+vecc)/3, (vecc+veca)/3` and `(veca+vecb)/3` respectively.
`:.V_(1)=1/6[(veca, vecb, vecc)]` and `V_(2)=[(vec(OG)_(1),vec(OG)_(2), vec(OG)_(3))]`
Now,
`V_(2)=[(vec(OG)_(1), vec(OG)_(2),vec(OG)_(3))]`
`impliesV_(2)=[((vecb+vecc)/3, (vecc+veca)/3, (veca+vecb)/3)]`
`implies V_(2)=1/27[(vecb+vecc, vecc+veca, veca+vecb)]=2/27[(veca, vecb, vecc)]=2/27xx6V_(1)`
`implies 9V_(2)=4V_(1)`