Taking O as the origin , let the position vectors of A,B and C be `veca , vecb and vecc`. Respectively, then the position vectors `G_(1), G_(2) and G-(3) are (vecb +vecc)/3,(vecc + veca)/(3) and (veca+vecb)/3` , respectively. Therefore,
`V_(1)=1/6[vecavecbvecc] and V_(2)=[vec(OG_(1))" "vec(OG_(2))" "vec(OG_(3))]`
`now,V_(2)=[vec(OG_(1))" "vec(OG_(2))" "vec(OG_(3))]`
`= 1/27 [ vecb + vecc vecc+veca veca +vecb]`
`=2/27 [ veca vecb vecc]`
`=2/27 xx6V_(1)or 9V_(2)=4V_(1)`