Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
59 views
in Vectors by (93.2k points)
closed by
Find a unit vector perpendicular to each of the vectors `( -> a+ -> b)` and `( -> a- -> b)` , where ` -> a= hat i+ hat j+ hat k , -> b= hat i+2 hat j+3 hat k` .

1 Answer

0 votes
by (94.4k points)
selected by
 
Best answer
Correct Answer - `pm(5(-hat(i)+2 hat(j) - hat(k)))/sqrt(6)`
`(pm 5[(vec(a) + vec(b)) xx ( vec(a) -vec(b))])/(|(vec(a)+ vec(b))xx(vec(a) - vec(b))|)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...