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The angle between the two tangents from the origin to the circle `(x-7)^2+ (y+1)^2= 25` equals
A. `pi//3`
B. `pi//6`
C. `pi//2`
D. `pi//8`

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Correct Answer - C
Let y=mx be a tangent drawn from the origin to the circle `(x-7)^(2)+(y+1)^(2)=5^(2)`.Then,
`(7m-(-1))/(sqrt(m^(2)+1))=pm5rArr12m^(2)+7m-12=0`.
Let `m_(1)` and `m_(2)` be the slopes of the two tangents. Then,
`m_(1)m_(2)=-(12)/(12)=-1`.
Hence, the angle between two tangents is `pi//2`
`ul("ALITER")` The director circle of hte given circle is
`(x-7)^(2)+(y+1)^(2)=50`
Clearly, (0, 0) lies on this circle. So, required angle is `pi//2`.

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