Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
98 views
in Chemistry by (88.1k points)
closed by
The molar conductances of `NaCl,HCl and CH_(3)COONa` at infinite dilution are 126.45, 426.16 and 91`ohm^(-1)cm^(2)mol^(-1)` respectively. The molar conductance of ` CH_(3)COOH` at infinite dilution is:-
A. `201.28ohm^(-1)cm^(2)mol^(-1)`
B. `390.71ohm^(-1)cm^(2)mol^(-1)`
C. `698.28ohm^(-1)cm^(2)mol^(-1)`
D. `540.48ohm^(-1)cm^(2)mol^(-1)`

1 Answer

0 votes
by (82.5k points)
selected by
 
Best answer
Correct Answer - B
`(^^)_(m)^(@)(CH_(3)COOH)`
`=(^^)^(@)(CH_(3)COONa)+(^^)^(@)(HCl)-(^^)^(@)(NaCl)`
`=91+426.16-126.45=390.71ohm^(-1)cm^(2)mol^(-1)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...