Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
397 views
in Chemistry by (93.5k points)
closed by
Platinum (II) forms square planar complexes and platinum (IV) gives octahedral complexes . Describe the structures of geometrical isomers of following compounds :
(1) `[Pt(NH_(3))_(3)Cl]^(+)` (2) `[Pt(NH_(3))Cl_(5)]^(-)`
(3) `[Pt(NH_(3))_(2)ClNO_(2)]` (4) `[Pt(NH_(3))_(4)ClBr]^(2+)`

1 Answer

0 votes
by (92.5k points)
selected by
 
Best answer
(1) No cis-trans isomerism is possible for `MA_(3)B` . image
(2) No Cis-trans isomerism for `MA_(5)B` image

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...