Question

Platinum (II) form's square planar complexes and platinum (IV) gives octahedral complexes. How many geometrical isomers are possible for each of the following. Draw their structures.

(a) [Pt(NH₃)₃Cl]⁺

(b) [Pt(NH₃)Cl₅]^–

(c) [Pt(NH₃)₂ClNO₂]

(d) [Pt(NH₃)₄Cl Br]⁺²

Answer 1

(a) No isomer is possible for a square planar complex MA₃B.

(b) No isomer is possible for an octahedral complex of the type MAB₅.

(c) cis-trans isomers are possible for a square planar complex MA₂BC.

(d) cis-trans isomers are possible for an octahedral complex of the type MA₂BC.