Question

A convex surface of radius of curvature 40 cm separate two media of refractive indices `(4)/(3)` and 1.50. An object is kept in the first medium at a distance of 20 cm from the surface. Calculate the position of the image.

Answer 1

`mu_(1) = (4)/(3), mu_(2) = 1.50, u = -20 cm, R = 40 cm`
`(mu_(2))/(v) - (mu_(1))/(u) = (mu_(2)-mu_(1))/(R)`
`(1.50)/(v) - (4)/((3)/(-20 cm)) = (1.50-(4)/(3))/(40 cm)`
v = -24 cm