`mu_(1) =100, mu_(2) = 1.34, u = - oo, R = 0.78 cm`
`(mu_(2))/(v) - (mu_(1))/(u) = (mu_(2)-mu_(1))/(R)`
`(1.34)/(v) - (1.00)/(-oo) = (1.34-1.00)/(0.78 cm)`
`v = 3.075 cm`
A real image forms in the second medium at a distance of 3.075 cm from the refracting surface.