Question

The de - Broglie wavelength of a particle moving with a velocity `2.25 xx 10^(8) m//s` is equal to the wavelength of photon. The ratio of kinetic energy of the particle to the energy of the photon is (velocity of light is `3 xx 10^(8) m//s`

Answer 1

`K_"particle"=1/2mv^2` also `lambda=h/"mv"`
`rArr K_"particle"=1/2(h/(lambdav))v^2=(vh)/(2lambda)`
`K_"photon"="hc"/lambda`
`therefore K_"particle"/K_"photon"=V/"2c"=(2.25xx10^8)/(2xx3xx10^8)=3/8`