Question

An electron and proton have same de-Broglie wavelength. Which one possess greater energy?

Answer 1

As `lambda=h/p` if `lambda_1=lambda_2` , then `p_1=p_2`
Now `E_e=p^2/(2M_e)` and `E_p=p^2/(2M_p)`
As `M_p gt M_e rArr E_e gt E_p`
hence, kinetic energy of electron is more than that of proton.