Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
68 views
in Physics by (93.5k points)
closed by
Find the ratio of de Broglie wavelength of molecules of hydrogen and helium which are at temperatures `27^circ` and `127^circC`, respectively.

1 Answer

0 votes
by (92.5k points)
selected by
 
Best answer
The translational kinetic energy of a molecule at a temperature T is `E=3/2kT`.
So, `lambda=h/sqrt(3mkT)` as `lambda=h/sqrt(2mE)`
`lambda_(H_2)/lambda_(He)=sqrt((m_"He"T_"He")/(m_(H_2)T_(H_2)))`
`lambda_(H_2)/lambda_"He"=sqrt(8/3)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...