Question

A stationary partical explodes into two partical of a masses `m_(1) and m_(2)` which move in opposite direction with velocities `v_(1) and v_(2)`. The ratio of their kinetic energies `E_(1)//E_(2)` is
A. `m_2//m_1`
B. `m_1//m_2`
C. 1
D. `m_1v_2//m_2v_1`

Answer 1

Correct Answer - A
`m_1v_1=m_2v_2(P_1=P_2)`
`E_1/E_2=(1/2m_1v_1^2)/(1/2m_2V_2^2)=((P_1^2)/(2m_1))/((P_2^2)/(2m_2))=m_2/m_1`