Question

The molar conductivity of `NH_(4)Cl` at infinite dilution is `149.7" S "cm^(2)` and the ionic conductivities of `OH^(-)` and `Cl^(-)` and are 198 and 96.3 S `cm^(2)` respectively. Calculate the molar conductivity of `NH_(4)OH` at this dilution.

Answer 1

Correct Answer - 271.4 S `cm^(2)mol^(-1)`
`wedge_(m)^(@)(NH_(4)OH)=lamda_(m)^(@)(NH_(4)Cl)-lamda_(m)^(@)(Cl^(-))+lamda_(m)^(@)(OH^(-))`