Question

Equivalent conductivity at infinite dilution for sodium potassium oxalate, `(COO^(-))_(2)Na^(+)K^(+)`, will be (given, molar conductivities of oxalate, `K^(+) and Na^(+)` ions at infinite diluton are `148.2,50.1,73.5" S "cm^(2)mol^(-1)` respectively).
A. `271.8" S "cm^(2)eq^(-1)`
B. `67.96" S "cm^(2)eq^(-1)`
C. `543.6" S "cm^(2)eq^(-1)`
D. `135.9" S "cm^(2)eq^(-1)`.

Answer 1

Correct Answer - D
`wedge_(m)^(@)` (Sod. Pot. Oxalate)`=lamda_(m)^(@)(Na^(+))+lamda_(m)^(@)(K^(+))+lamda^(2)`(oxalate)
`=(50.1+73.5+148.2)" S "cm^(2)mol^(-1)`
`=271.8" S "cm^(2)mol^(-1)`
`wedge_(eq)^(@)=(wedge_(m)^(@))/("Total chrge on cations or anions (n factor)")`
`=(271.8)/(2)=135.9" S "cm^(2)eq^(-1)`.