Question

Given that the standard electrode potential `(E^(@))` of metals are:
`K^(+)//K=-2.93V,Ag^(+)//Ag=0.80V," "Cu^(2+)//Cu=0.34V,Mg^(2+)//Mg=-2.37V`,
`Cr^(3+)//Cr=-0.74V,Fe^(2+)//Fe=-0.44V`
Arrange these metals in an increasing order of their reducing power.

Answer 1

Higher the oxidation potential more easily it is oxidised and hence stronger is the reducing power. Therefore order is `Ag lt Cu lt Fe lt Mg lt K`.