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For the cell, `TI|TI^(+)(0.001M)|Cu^(2+)(0.1M)|Cu,E_(cell)` at `25^(@)C` is 0.83 V. this can be increased
A. by increasing `[Cu^(2+)]`
B. by increasing `[TI^(+)]`
C. by decreasing `[Cu^(2+)]`
D. by decreasing `[TI^(+)]`

1 Answer

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Best answer
Correct Answer - A::D
`2TI+Cu^(2+)to2TI^(+)+Cu,E_(cell)-E_(cell)^(@)-(0.0591)/(2)"log"([TI^(+)]^(2))/([Cu^(2+)])`

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