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The radius of germanium `(Ge)` nuclide is measured to be twice the radius of `._(4)^(9)Be`. The number of nucleons in `Ge` are
A. 73
B. 74
C. 75
D. 72

1 Answer

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Best answer
Correct Answer - D
`R=R_(0)A^(1//3)impliesA_(G_(e))=((R_(G_(E)))/R_(V_(e)))^(3)(A_(B_(e)))=(2)^(3)(9)`
`8xx9=72`

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