Question

A charged particle of mass `m` and charge `q` is accelerated through a potential differences of `V` volts. It enters of uniform magnetic field `B` which is directed perpendicular to the direction of motion of the particle. The particle will move on a circular path of radius
A. `((sqrtVm)/(2qB^2))`
B. `(2Vm)/(qB^2)`
C. `sqrt((2Vm)/q)(1/B)`
D. `sqrt((Vm)/q) (q/B)`

Answer 1

Correct Answer - C
`r=sqrt((2qVm)/(Bq))=(sqrt((2Vm)/q))(1/B)`