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In the circuit shown in figureure, the reading of the `AC` ammeter is .

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In the circuit shown in figureure, the reading of the `AC` ammeter is
image.
A. `20sqrt2mA`
B. `40sqrt2mA`
C. `20mA`
D. `40mA`
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Correct Answer - C
`X_C=1/(omegaC)=1/(100xx10^-6)=10^4Omega`
`I_("rms")=V_("rms")/X_C=((200sqrt(2)//sqrt(2)))/10^(4)`
`=0.02A=20mA`.
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