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In the `AC` network shown in figureure the rms current flowing through the inductor and capacitor are `0.6 A` and `0.8A`, respectively. Then the current coming out of the source is
image.
A. `1.0A`
B. `1.4A`
C. `0.2A`
D. none of the above

1 Answer

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Best answer
Correct Answer - C
`I_C` is `90^@` a head of the applied votage and `I_L` lags behind the applied voltage by `90^@`. So, there is a phase difference of `180^@` between `I_L and I_C`.
`:. I=I_C=I_L=0.2A`

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