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A proton and an alpha - particle are accelerated through same potential difference. Then, the ratio of de-Broglie wavelength of proton and alpha-parti

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A proton and an alpha - particle are accelerated through same potential difference. Then, the ratio of de-Broglie wavelength of proton and alpha-particle is
A. `sqrt2`
B. `(1)/(sqrt2)`
C. `2sqrt2`
D. None of these
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Correct Answer - C
`:. lambda = (h)/(sqrt2qvm) or lambda prop (1)/(sqrtqm)`
`:. (lambda_p)/(lambda_(alpha)) =(sqrtqm)_(alpha)/(sqrtqm)_p =sqrt(2xx4)/sqrt(1xx1) = 2sqrt2`
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