Question

A copper coil has resistance of `20.0 Omega at 0^@C` and a resistance of `26.4 Omega at 80^@C`. Find the temperature coefficient of resistance of copper.

Answer 1

`R_(80^@C) = R_(0^@C)[1 + alpha Delta T]`
or `26.4 = 20.0 [1+alphaxx(80 - 0)] or (26.4)/(20) = 1+80 alpha`
On solving, we get ` alpha = 4xx10^(-3^@)C^(-1).`