Question

At room temperature `(27^@C)` the resistance of a heating element is `100 Omega.` Wheat is the temperature of the element is the resistace is found to `117Omega?` Given that the teperature coefficint of the meterail of the resistor is `1.70xx10^(-40) C^(-1)`

Answer 1

Temperature coefficients of the meterial is given by
`alpha = (R_(2) - R_(1))/(R_(1)(t_(2) - t_(1))) or 1.790xx10^(-4) = (117 - 100)/(100(t_(2) - 27))`
or `t_(2) = 1000 +27 =1027^(@)C`