Question

Resistance of a resistor at temperature `t^@C is R_t =R_0 (1+alphat + betat^2)`, where `R_0` is the resistance at `0^@C`. The temperature coeffcient of resistance at temperature `t^@C` is
A. `((1+alphat+betat^2))/(alpha+2beta t)`
B. `(alpha+2beta t)`
C. `(alpha +2 beta t)/((1 +alphat + beta t^2))`
D. `(alpha +2betat)/(2(1+alpaht +beta r^2))`

Answer 1

Correct Answer - C
`alpha = (1)/(R_(t))(dR_(t))/(dt) = (1)/(R_t)=(1)/(R_t) R_0 [ alpha +2betat]`
`alpha=(R_(0)[alpha+2betat])/(R_(0)[1+alpha t+betat^(2)])=(alpha+2betat)/(1+alpha t+beta t^(2))`