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in Physics by (92.0k points)
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In the circuit shown in fig. 5.265, `E_1 = E_2 = E_3 = 2V` and `R_1 = R_2 = 4Omega.` The current flowing between points A and B through battery `E_2` is
image
A. zero
B. 2 A from A to B
C. 2 A form B to A
D. none of the above

1 Answer

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by (92.8k points)
 
Best answer
Correct Answer - B
For loop (1), `2 + 2 -4I_1 = 0 or I_1 = 1 A`
image
For loop (2), `-2 -2 +4I_(2) = 0 or I_(2) = 1A`
So the current from A to B is `I_(1) +I_(2) = 2A`.

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