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A platinum wire has a resistance of `10Omega at 0^@C and 20Omega at 273^@C.` find the value of temperaure cofficient of platinum.

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`alpha = (R_(1) - R_(0))/(R_(0)t) = (R_(20) - R_(0))/(R_(0)xx273) =(20-10)/(10xx273)= (1)/(273) = (1) /(273). ^(@)C^(-1) or K^(-1)`

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