Question

The image of point P when viewd from top of the slabs will be

A. 2.0cm above P
B. 1.5 cm above P
C. 2.0cm below P
D. 1cm above P

Answer 1

Correct Answer - d.
The two slabs will shift the image a distance
`d=2(1-(1)/(mu))t=2(1-(1)/(1.5))(1.5)=1.0cm`
Therefore, final image will be 1cm above point P.