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The image of point `P` when viewed from top of the slabs will be

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The image of point `P` when viewed from top of the slabs will be
image
A. `2.0cm` above `P`
B. `1.5cm` above `P`
C. `2.0 cm` below `P`
D. `1 cm` above `P`
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Correct Answer - D
The two slabs will shift the image a distance
`d=2(1+(1)/(mu))t=2(1-(1)/(1.5))(1.5)=1.0 cm`
Therefore, final image will be `1 cm` above point `P`.
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