Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
250 views
in Physics by (89.5k points)
closed by
An object ABED is placed in front of a concave mirror beyond the center of curvature C as shown in figure., State the shape of the image.
image
A. `|m_(AB)|lt1 and |m_(ED)|lt1`
B. `|m_(AB)|gt1 and |m_(ED)|lt1`
C. `|m_(AB)|lt1 and |m_(ED)|gt1`
D. `|m_(AB)|gt1 and |m_(ED)|gt1`

1 Answer

0 votes
by (94.2k points)
selected by
 
Best answer
Correct Answer - a.
Objec t is placed beyond C. Hence, the image will be real and it will lie between C and F. Further u, and v are negative, hence the mirror formula will become
`(1)/(v)+(1)/(u)=(1)/(f)`
`(1)/(v)+(1)/(u)=(1)/(f)=(u-f)/(uf) or v=(f)/(1-(f//u))`
Now, `u_(AB) gt u_(ED)`
`:.u_(AB) gt v_(ED)`
`|m_(AB)| lt |m_(ED)| (" as" m=-(v)/(u))`
Therefore, shape of the image will be as shown in figure.
Also, note that, `v_(AB) lt u_(AB) and v_(ED) lt u_(ED)`,
So, `|m_(AB)| lt 1` and `|m_(ED)| lt 1`
image

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...