Correct Answer - c.
According to given problem, for concave mirror,
`u=-15cm` and `f=-10cm`
`(1)/(v)+(1)/(-15)=(1)/(-10), i.e, v=-30cm`
i.e., concave mirror will form real, inverted, and enlarged image `I_(1)` of object O at a distance of 30cm from it, i.e., at a distance `40-30=10cm` from the convex mirror.
For convex mirror, the image `I_(1)` will act as an object and so for it `u=-10cm ` and `f=+15cm`.
`(1)/(v)+(1)/(-10)=(1)/(15), i.e., v=+6cm`
So, final image `I_(2)` is formed at a distance of 6cm behind the convex mirror and is virtual as shown in figure .
