Question

Consider the reaction `._1^2H+_1^2H=_2^4He+Q`. Mass of the deuterium atom`=2.0141u`. Mass of helium atom `=4.0024u`. This is a nuclear………reaction in which the energy `Q` released is…………MeV.

Answer 1

This is a nuclear fusion reaction.
Energy released`=(Delta m)[(931.5 MeV//u]`
`=[4.0024 -2 xx 2.0141]xx931.5 MeV`
` = -24.03 MeV` (heat release)