Question

The order of magnitude of the density of nuclear matter is `10^(4) kg m^(-3)`

Answer 1

False .
Density `=(m)/(V) =(Axx1.67xx10^(27))/((4)/(3)pi[R_(0)A^(1//3)])=3xx10^(17)kg m^(-3)`.
where `A=` mass number
`=(1.67xx10^(-27))/(1.33xx3.14xx(1.1xx10^(-15))`
Alternative solution :
Remember that the order of nuclear density is `10^(17) kg m^(-3)`.