Question

Three capacitors each of capacitance `C` and of breakdown voltage `V` are joined in series. The capacitance and breakdown voltage of the combination will be
A. `(C )/(3), (V)/(3)`
B. `3C, (V)/(3)`
C. `(C )/(3), 3V`
D. `3C, 3V`

Answer 1

Correct Answer - C
In series combination charge on each plate of each capacitor has the same magnitude.
The potential difference is distributed inversely in the ratio of capacitors, i.e.,
`V = V_(1) + V_(2) + V_(3)`..
Here, `V = 3V`
The equivalent capacitance `C_(s)` is given by
`(1)/(C_(s)) = (1)/(C_(1))+(1)/(C_(2))+(1)/(C_(3))+..`
`C_(s) = (C )/(3)`