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+1 vote
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in Physics by (93.7k points)
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In the circuit `P != R, ` the reading of the galvanometer is same with switch S open or closed. Then
image
A. `I_(R) = I_(G)`
B. `I_(P) = I_(G)`
C. `I_(Q) = I_(G)`
D. `I_(Q) = I_(G)`

1 Answer

+1 vote
by (94.0k points)
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Best answer
Correct Answer - A
(a) Reading of galvanometer remains same whether switch `S` is open or closed, hence no current will flow through the switch i.e., `R` and `G` will be in series and same current will flow through them. `I_(R) = I_(G)`.

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