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+1 vote
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in Physics by (90.6k points)
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In the circuit `P != R, ` the reading of the galvanometer is same with switch S open or closed. Then
image
A. `I_(R)=I_(G)`
B. `I_(P)=I_(G)`
C. `I_(Q)=I_(G)`
D. `I_(Q)=I_(R)`

1 Answer

+1 vote
by (88.6k points)
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Best answer
Correct Answer - A
As there is no change in the reading of galvanometer with switch S open or closed. It implies that bridge is balanced current through S is zero and `I_(R)=I_(G),I_(P)=I_(Q)`

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