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A `100%` efficient transformer has `100` turns in the primary and `25` turns in its secondary coil. Of the current in the secondary coil is `4` amp, then the current in the primary coil is
A. `1` amp
B. `4` amp
C. `8` amp
D. `16` amp

1 Answer

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Best answer
Correct Answer - A
For `100%` efficient transformer
`V_(s)i_(s)=V_(p)i_(p)implies(V_(s))/(V_(p))=(i_(p))/(i_(s))=(N_(s))/(N_(p))implies(i_(p))/(4)=(25)/(100)i_(p)=1A`

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