Question

In a lossless transformer an alternating current of `2` amp is flowing in the primary coil. The number of turns in the primary and secondary coils are `100` and `20` respectively. The value of the current in the secondary coil is
A. `0.08A`
B. `0.4A`
C. `5A`
D. `10A`

Answer 1

Correct Answer - D
`(N_(s))/(N_(p))=(i_(p))/(i_(s))impliesi_(s)=i_(p)xx(N_(p))/(N_(s))=2xx(100)/(20)=10A`