Correct Answer - D
`Z=sqrt((R)^(2)+(X_(L)-X_(C))^(2))`,
`R=10 Omega, X_(L)=omegaL=2000xx5xx10^(-3)=10 Omega`
`X_(C)=1/(omegaC)=1/(2000xx50xx10^(-6))=10 Omega i.e., Z=10 Omega`
Maximum current `i_(0)=(V_(0))/Z=20/10=2A`
Hence `i_(rms)=2/(sqrt(2))=1.4A`
and `V_(rms)=4xx1.41=5.46 V`