Question

The de - Broglie wavelength `lambda` associated with an electron having kinetic energy `E` is given by the expression
A. `(h)/(sqrt( 2 m E))`
B. `( 2h)/(m E)`
C. `2 mhE`
D. `( 2 sqrt(2 mE))/(h)`

Answer 1

Correct Answer - A
`(1)/(2) mv^(2) = E rArr = mv = sqrt(2 m E) , :. E = (h)/( mv) = (h)/(sqrt( 2m E))`