Question

For what kinetic energy of a proton, will the associated de-Broglie wavelength be 16.5nm? Mass of proton `=1.675xx10^(-27)kg , h=6.63xx10^(-34)Js`

Answer 1

Here, `lambda=16.5nm=16.5xx10^-9m`
K.E. of proton,
`K=1/2 (mv^2)= 1/(2m) (mv^2)=1/(2m) (h^2)/(lambda^2)`
`=((6.63xx10^(-34))^2)/(2xx(1.675xx10^(-27))xx(16.5xx10^-9)^2)`
`=4.82xx10^(-25)J`