Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
4.6k views
in Physics by (97.8k points)
closed by
Find the number of photons emitted per minute by a 25W source of monochromatic light of wavelength 5000Å. Use `h=6.63xx10^(-34)Js`.

1 Answer

0 votes
by (98.2k points)
selected by
 
Best answer
Correct Answer - `3.77xx10^(21)`
Here, `P=25W, t=60s`,
`lambda=5000Å=5xx10^(-7)m`,
Energy of a photon,
`E=(hc)/lambda=(6.63xx10^(-34)xx3xx10^(8))/(5xx10^(-7))`
`=3.978xx10^(-19)J`
Energy emitted by source perminute`=E_(1)=Pt`
`E_(1)=25xx60=1500J`.
No. of photons emitted per minute
`N=1500/(3.978xx10^(-19))=3.77xx10^(21)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...