Question

Energy of an electron in an excited hydrogen atom is `-3.4eV`. Its angualr momentum will be: `h = 6.626 xx 10^(-34) J-s`.
A. `1.11 xx 10^(34) J-s`
B. `1.51 xx 10^(-31)J-s`
C. `2.11 xx 10^(-34)J-s`
D. `3.72 xx 10^(-34)J-s`

Answer 1

Correct Answer - C
The elctron is in the second orbit `(n = 2)`
Hence `L = (nh)/(2pi) = (2h)/(2pi) = (6.6 xx 10^(-34))/(pi)`
`= 2.11 xx 10^(-34) J-sec`