Energy of an electron in an excited hydrogen atom is `-3.4eV`. Its angualr momentum will be: `h = 6.626 xx 10^(-34) J-s`.

Correct Answer - `2.11xx10^(-34)Js`
`E=(-13.6)/(n^(2))=-3.4eV :. n=2`
`:.` Angular momentum of electron
`=(nh)/(2pi)=2h//2pi=h/pi=(6.626xx10^(-34))/3.14`
`2.11xx10^(-34)J-s`

Energy of an electron in an excited hydrogen atom is `-3.4eV`. Its angualr momentum will be: `h = 6.626 xx 10^(-34) J-s`.

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