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A common emitter amplifier is designed with `NPN` transistor `(alpha=0.99)`. The input impedence is `1k Komega` and load is `10 Komega`. The voltage g

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A common emitter amplifier is designed with `NPN` transistor `(alpha=0.99)`. The input impedence is `1k Komega` and load is `10 Komega`. The voltage gain will be
A. `9.9`
B. `99`
C. `990`
D. `9900`
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Correct Answer - C
Voltage gain `=betaxx` Resistance gain
`beta=(alpha)/(1+alpha)=0.99/((1-0.99))=99`
Resistance gain `=(10xx10^(3))/(10^(3))=10`
`implies` Voltage gain `=99xx10=990`
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