Correct Answer - (i) `6 xx 10^(-3) rad`. (ii) `6 xx 10^(-4) m`
Here, `lambda = 6000 Å = 6 xx 10^(-7)m` ltbr. `d = 0.1 cm = 10^(-3), D = 1 m, n = 10`
`x = n lambda(D)/(d)`. If `theta` is angle of diffraction, then
`sin theta = (x)/(D) = (s lambda)/(d) = (10 xx 6 xx 10^(-7))/(10^(-3)) = 6 xx 10^(-3)`
As `sin theta` is small, `theta ~~ sin theta = 6 xx 10^(-3)rad`
(ii) Separation of two adjacent minima
`beta = (lambda D)/(d) = (6 xx 10^(-7) xx 1)/(10^(-3)) = 6 xx 10^(-4)m`