Correct Answer - D
Electron beam serves as a light wave. As width `(d)` of slit is comparable to de-Broglie wavelength, therefore, the electron beam is diffracted on passing through the slit.
We obtain a central maximum surrouded by secondary minima and maxima placed alternately. The intensity is represented by `N` and in diffraction pattern, intensity is never zero. Therefore, choice `(d)` refresents the correct graph, in Fig.