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A heavy nucleus X of mass number `240` and binding energy per nucleon `7.6 MeV` is split into two fragments Y and Z of mass numbers `110` and `130`. The binding energy of nucleons in Y and Z is `8.5MeV` per nucleon. Calculate the energy Q released per fission in MeV.

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Correct Answer - 216 MeV
Here, `X^(220)toY^(110)+Z^(130)`
Energy released `110xx8.5+130xx8.5-240xx7.6`
`=935+1105-1824=216MeV`

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