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Calculate the half life periode of a radioactive substance if its activity drops to `1/16` th of its initial value of 30 yr.

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Calculate the half life periode of a radioactive substance if its activity drops to `1/16` th of its initial value of 30 yr.
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Correct Answer - `7.5 yr`
`T=?, N/(N_(0))=1/16, t=30years`
As `N/(N_(0))=(1/2)^(n)=1/16=(1/2)^(4)`
`:. n=4=t/T,T=t/4=30/4=7.5 years`
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