Question

Find the average value of d.c. voltage that can be obtained from the half wave rectifier of Fig. assuming that the diode is ideal one.

Answer 1

Max. value of the input voltage,`V_(0)=sqrt(2)V_(rms)=sqrt(2)xx200=282.8V` to primary of transformer Max. value of output voltage across secondary of transformer `V_(s)=n_(s)/n_(p)xxV_(p)=1/10xx282.8=28.28V`
d.c. voltage across the load is
`V_(dc)=V_(s)/pi=28.28/3*142=9.0V`